an=a1×rn−1.a_n = a_1 \times r^{n-1}.an=a1×rn−1. So we have found. □ \begin{array} { rllll} -4A&=3-3 \cdot 5^{10}\\\\ \ _\squareSn=a×(r−1rn−1) for r=1. can be written as a, ar, ar2, ar3,……arn-1. To learn more about Arithmetic Progressio. When −1 Active Noise Cancellation Earphone,
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